# Talk:1124: Law of Drama

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::It could be a shallow power function curve . . .--[[User:Joehammer79|Joehammer79]] ([[User talk:Joehammer79|talk]]) 13:57, 22 October 2012 (UTC) | ::It could be a shallow power function curve . . .--[[User:Joehammer79|Joehammer79]] ([[User talk:Joehammer79|talk]]) 13:57, 22 October 2012 (UTC) | ||

− | :I took 26 data points, assumed the axes defined a (0-1,0-1) window, and tried an extrapolation (using Microsoft Excel; someone with a different tool can surely do better). An exponential model fits fairly well: y = 0.0782 * e^(2.7035*x) with R^2 = 0.9928. However, I agree about the linear end section -- the exponential trendline | + | :I took 26 data points, assumed the axes defined a (0-1,0-1) window, and tried an extrapolation (using Microsoft Excel; someone with a different tool can surely do better). An exponential model fits fairly well: y = 0.0782 * e^(2.7035*x) with R^2 = 0.9928. However, I agree about the linear end section -- the exponential trendline clearly starts to pull high. --BigMal27 // [[Special:Contributions/192.136.15.149|192.136.15.149]] 13:57, 22 October 2012 (UTC) |

I think Randall thought about the shape of this curve. You see how it becomes linear as both drama and anti-drama declaration increase? At low values, there is a residual amount of drama even when there is little anti-drama declaration, but the marginal increase eventually becomes constant. --[[User:Prooffreader|Prooffreader]] ([[User talk:Prooffreader|talk]]) 11:28, 22 October 2012 (UTC) | I think Randall thought about the shape of this curve. You see how it becomes linear as both drama and anti-drama declaration increase? At low values, there is a residual amount of drama even when there is little anti-drama declaration, but the marginal increase eventually becomes constant. --[[User:Prooffreader|Prooffreader]] ([[User talk:Prooffreader|talk]]) 11:28, 22 October 2012 (UTC) |

## Revision as of 17:44, 22 October 2012

Regarding the transcript: I don't think you have enough data to characterize this short curve as exponential. What does "slightly exponential" mean, anyway? In any case, it looks like it becomes linear as the x values increase. --Prooffreader (talk) 11:21, 22 October 2012 (UTC)

- It could be a shallow power function curve . . .--Joehammer79 (talk) 13:57, 22 October 2012 (UTC)

- I took 26 data points, assumed the axes defined a (0-1,0-1) window, and tried an extrapolation (using Microsoft Excel; someone with a different tool can surely do better). An exponential model fits fairly well: y = 0.0782 * e^(2.7035*x) with R^2 = 0.9928. However, I agree about the linear end section -- the exponential trendline clearly starts to pull high. --BigMal27 // 192.136.15.149 13:57, 22 October 2012 (UTC)

I think Randall thought about the shape of this curve. You see how it becomes linear as both drama and anti-drama declaration increase? At low values, there is a residual amount of drama even when there is little anti-drama declaration, but the marginal increase eventually becomes constant. --Prooffreader (talk) 11:28, 22 October 2012 (UTC)

- I think that the upper limit for drama statements does indeed have an end-point, beyond which those declarations can't increase. At that point, I suppose, the drama-ridden person experiences a split state-change, either dropping to the original non-drama state by disavowing all the causers-of-drama in their lives, or by becoming a causer-of-drama.--Noni Mausa (talk) 13:11, 22 October 2012 (UTC)

- At this point in the discourse, I'm reminded of a real-scientist friend who admonished me once for reading too much into some data, and it seems applicable here, too. To wit: the axes are not labeled with units -- no tick marks to be seen anywhere -- nor is it clear what sort of axes are in use: log, logit, probit? Randall, not being the naïve sort, likely understands this, and merely shows us a graph that suggest a slightly accelerating direct relationship between the two axes. If the axes are linear, the curve has the characteristic upward swing of an exponential, but we don't
*know*that, and any conjecture beyond observable facts is inappropriate. To leap to application of, say Levenberg-Marquardt, seems folly. (As an aside, I'm reminded of the old Benny Hill skit, where he's a movie director being interviewed on some talking-heads show; says the interviewer: "I particularly enjoyed the poignancy of suddenly switching to black and white film right as..." Benny Hill: "Rubbish, we just ran out of film, and black and white was all we had left.") -- IronyChef (talk) 14:23, 22 October 2012 (UTC)

- At this point in the discourse, I'm reminded of a real-scientist friend who admonished me once for reading too much into some data, and it seems applicable here, too. To wit: the axes are not labeled with units -- no tick marks to be seen anywhere -- nor is it clear what sort of axes are in use: log, logit, probit? Randall, not being the naïve sort, likely understands this, and merely shows us a graph that suggest a slightly accelerating direct relationship between the two axes. If the axes are linear, the curve has the characteristic upward swing of an exponential, but we don't