Talk:1132: Frequentists vs. Bayesians

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:: Our sun will not go supernova, as it has insufficient mass.  It will slowly become hotter, rendering Earth uninhabitable in a few billion years.  In about 5 billion years it will puff up into a red giant, swallowing the inner planets.  After that, it will gradually blow off its lighter gasses, eventually leaving behind the core, a white dwarf. [[Special:Contributions/50.0.38.245|50.0.38.245]] 01:58, 15 November 2012 (UTC)
 
:: Our sun will not go supernova, as it has insufficient mass.  It will slowly become hotter, rendering Earth uninhabitable in a few billion years.  In about 5 billion years it will puff up into a red giant, swallowing the inner planets.  After that, it will gradually blow off its lighter gasses, eventually leaving behind the core, a white dwarf. [[Special:Contributions/50.0.38.245|50.0.38.245]] 01:58, 15 November 2012 (UTC)
  
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:::Please don't edit others' comments on talk pages; it's considered quite rude. On a talk page, discourse is meant to be conducted, by editors for the betterment of the article. For constructive discourse to occur, a person's words must be left in tact. The act of censorship hurts the common goal of betterment. Per [http://en.wikipedia.org/wiki/Wikipedia:Talk_page_guidelines#Editing_comments Wikipedia], the authoritative source on how a wiki works best: "you ''should not'' edit or delete the comments of other editors without their permission." [[User:Lcarsos|lcarsos]]<span title="I'm an admin. I can help.">_a</span> ([[User talk:Lcarsos|talk]]) 17:38, 13 November 2012 (UTC) <small>Note: much of this conversation has been removed at the request of the authors.</small>
:::I left your comment here so I can set you straight on something. '''''DO NOT EVER''''' edit any editor's comments on a discussion page. You can reply to their comment, but you do not edit another person's words. You do that again, you get the banhammer. [[User:Lcarsos|lcarsos]] ([[User talk:Lcarsos|talk]]) 17:38, 13 November 2012 (UTC)
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:::: Quote from the instructions at the bottom of the discussion edit page: "Please note that all contributions to explain xkcd '''may be edited, altered, or removed by other contributors'''. If you do not want '''your writing to be edited mercilessly''', then do not submit it here." But don't worry, I won't be contributing again, if it can be met with this kind of attitude.[[Special:Contributions/50.0.38.245|50.0.38.245]] 01:58, 15 November 2012 (UTC)
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:::::If you'll note, those instructions are on the bottom of every edit page. Indeed, the notice is intended to be for article pages, where it is encouraged that an editor with an improvement, improve upon the words of another editor. However, on a talk page, discourse is meant to be conducted, by editors for the betterment of the article. For constructive discourse to occur, a person's words must be left in tact. The act of censorship hurts the common goal of betterment. Per [http://en.wikipedia.org/wiki/Wikipedia:Talk_page_guidelines#Editing_comments Wikipedia], the authoritative source on how a wiki works best: "you ''should not'' edit or delete the comments of other editors without their permission." I encourage, nay, ''implore'', you to assist in the improvement this wiki. But please, do it without editing other people's comments on a talk page, that's simply rude. [[User:Lcarsos|lcarsos]]<span title="I'm an admin. I can help.">_a</span> ([[User talk:Lcarsos|talk]]) 01:08, 15 November 2012 (UTC)
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I think the explanation is wrong or otherwise lacking in its explanation: The P-value is not the entire problem with the frequentist's viewpoint (or alternatively, the problem with the p-value hasn't been explained). The Frequentist has looked strictly at a two case scenario: Either the machine rolls 6-6 and is lying, or it doesn't rolls 6-6 and it is telling the truth. Therefore, there is a 35/36 probability (97.22%) that the machine is telling the truth and therefore the sun has exploded. The Bayesian is factoring in outside facts and information to improve the accuracy of the probability model. He says "Either the machine rolls 6-6 (a 1/36 probability, or 2.77%) or the sun has exploded (an aparently far less likely scenario). Given the comparison, the Bayesian believes it is MORE probable that the machine rolled 6-6 than the sun exploded, given the relative probabilities. If the latter is a 1 in a million chance (0.000001%), it is 2,777,777 times more likely that the machine rolled 6-6 than the sun exploded.
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To borrow a demonstration/explanation technique from the Monty Hall problem, if the machine told you a coin flip was heads, that would be 50% chance of occuring while a 2.7% chance of the machine lying, the probabilities would clearly suggest that the machine was more likely to be telling the truth. Whereas if the machine said that 100 coin flips had all come up heads (7.88x10^-31%). Is it more likely that 100 coin flips all came up heads or is it more likely the machine is lying? What about 1000 coin flips? or 1,000,000? I think the question is, whether one could assign a probability to the sun exploding. Also, I think they could have avoided the whole thing by asking the machine a second time and see what it answered. [[User:TheHYPO|TheHYPO]] ([[User talk:TheHYPO|talk]]) 19:09, 12 November 2012 (UTC)
  
::::::This was my first time contributing to a wiki discussion page. There was nothing written here to lead me to believe that it was different in this regard from any other wiki page; quite the opposite, as I mentioned.  Perhaps you can find a way to describe this exception in the instructions at the bottom of the edit page.  I'm sure you found out or helped form this bit of wiki etiquette long ago, but people who are new to contributing should not be verbally assaulted for not having heard of it already.  And by an admin, no less.[[Special:Contributions/50.0.38.245|50.0.38.245]] 01:58, 15 November 2012 (UTC)
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Another source of explanation: http://stats.stackexchange.com/questions/43339/whats-wrong-with-xkcds-frequentists-vs-bayesians-comic --[[User:JakubNarebski|JakubNarebski]] ([[User talk:JakubNarebski|talk]]) 20:12, 12 November 2012 (UTC)
  
:::::::Explain XKCD follows the editing guidelines followed by mainline Wikipedia by default. The policy page in question is {{w|WP:TPO}}. Editing other people's talk page entries tends to be frowned upon as it leads to misrepresentation of other people's opinions. [[User:Davidy22|<span title="I want you."><u><font color="purple" size="2px">David</font><font color="green" size="3px">y</font></u><sup><font color="indigo" size="1px">22</font></sup></span>]][[User talk:Davidy22|<tt>(talk)</tt>]] 03:21, 15 November 2012 (UTC)
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The P-value really has nothing to do with it. If I think that there is a 35/36 chance that the sun has exploded, then I should we willing to take any bet that the sun has exploded with better than 1:35 odds. For example, if someone bets me that the sun has exploded in which they will pay me $2 if the sun has exploded and I will pay them $35 if it hasn't, then based on my belief that the sun has exploded with 35/36 probability, then my expected value for this bet is 2*35/36 - 35 * 1/36 = 35/36 dollars and I will take this bet.  Clearly I would also take a bet with 1:1 odds - my estimated expected value in the proposed bet in the comic would be 50*35/36 - 50 * 1/36 = $49 (approximately), and I would for sure take this bet.  The Bayesian on the other hand has a much lower belief that the sun has exploded because he takes into account the prior probability of the sun exploding, so he would take the reverse side of the bet.  The difference is that the Bayesian uses prior probabilities in computing his belief in an event, whereas frequentists do not believe that you can put prior probabilities on events in the real world.  Also note that this comic has nothing to do with whether people would die if the sun went nova - the comic is titled "Frequentists vs Bayesians" and is about the difference between these two approaches. {{unsigned|171.64.68.120}}
  
::::::::And it's appropriate to threaten to ban someone permanently from the site when they mistakenly break this rule once?  Isn't there a line on the main page that says "Don't be a jerk"?[[Special:Contributions/50.0.38.245|50.0.38.245]] 05:32, 15 November 2012 (UTC)
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The Labyrinth reference reminds me of an old Doctor Who episode (Pyramid of Mars), where the Doctor is also faced with a truthful and untruthful set of guards. Summarized here: http://tardis.wikia.com/wiki/Pyramids_of_Mars_(TV_story) [[User:Fermax|Fermax]] ([[User talk:Fermax|talk]]) 04:49, 14 November 2012 (UTC)
  
:::::::::There is no possible way for me to answer this without coming off like a jerk. See "{{w|Loaded question|When did you stop beating your wife?}}". Either I say, yes it's appropriate, in a "give one warning, then consequences" "spare the rod, spoil the child" kind of way and seem like hard-ass. Or I say no, and become a hypocrite. So all I'm going to say is, Welcome to explain xkcd, a wiki devoted to explaining xkcd. Please help better the wiki, ask questions if you need help or don't understand something, and someone will let you know if you've overstepped your bounds. We don't have any official rules written specifically for here but [http://en.wikipedia.org/wiki/Help:Getting_started Wikipedia] does. <small>P.S. simply being around for awhile does not make me infallible, I'm still human, prone to anachronistic failures. There I said it.</small> [[User:Lcarsos|lcarsos]]<span title="I'm an admin. I can help.">_a</span> ([[User talk:Lcarsos|talk]])  06:30, 15 November 2012 (UTC)
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This is actually an example of the [https://en.wikipedia.org/wiki/Base_rate_fallacy Base rate fallacy]. --[[Special:Contributions/71.199.125.210|71.199.125.210]] 04:04, 19 November 2012 (UTC)
  
::::::::::I guess your "only human" statement is as close as you'll come to an apology for your excessive harshness.  So a bit of advice: if you're "imploring" people to contribute, perhaps you should be setting an example of an environment that is ''not'' a minefield.[[Special:Contributions/50.0.38.245|50.0.38.245]] 07:30, 15 November 2012 (UTC)
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People have gone over this already, but just to be a bit more explicit:
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Let NOVA be the event that there was a nova, and let YES be the event that the detector responds "Yes" to the question "Did the sun go nova?"
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What we want is P(NOVA|YES)=P(YES|NOVA)*P(NOVA)/P(YES)
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Suppose P(NOVA)=p is the prior probability of a nova.
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Then P(YES|NOVA)=35/36, P(NOVA)=p, and P(YES)=p*35/36+(1-p)*1/36=1/36+34/36
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So then P(NOVA|YES)=35p/(1+34p). If p is small, then P(NOVA|YES) is also small. In particular, the Bayesian statistician wins his bet at 1:1 odds if p<1/36, which is probably the case.
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If the Bayesian statistician wants 95% confidence that he'll win his bet, then he needs p<1/666. =P
  
:::::::::: To try to clarify further: this was not simply "one warning, then consequences."  It's more like "one warning, then death."  As if a cop shoved his gun in someone's face for failing to use turn signals.[[Special:Contributions/50.0.38.245|50.0.38.245]] 07:40, 15 November 2012 (UTC)
 
  
:::::::::::This discussion adds no value to the relevant page, and so I have hidden it from regular view. Please cease this argument or take it to a user talk page. [[User:Davidy22|<span title="I want you."><u><font color="purple" size="2px">David</font><font color="green" size="3px">y</font></u><sup><font color="indigo" size="1px">22</font></sup></span>]][[User talk:Davidy22|<tt>(talk)</tt>]] 08:17, 15 November 2012 (UTC)
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It's cute to attempt to connect this to the U.S. presidential election, but it's far likelier that it's a reference to Enrico Fermi taking bets at the Trinity test site as to whether or not the first atomic bomb would cause a chain reaction that would ignite the entire atmosphere and destroy the planet. I'll bet you $50 it is. [[Special:Contributions/71.229.88.206|71.229.88.206]] 21:29, 7 March 2013 (UTC)
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I think the explanation is wrong or otherwise lacking in its explanation: The P-value is not the entire problem with the frequentist's viewpoint (or alternatively, the problem with the p-value hasn't been explained). The Frequentist has looked strictly at a two case scenario: Either the machine rolls 6-6 and is lying, or it doesn't rolls 6-6 and it is telling the truth. Therefore, there is a 35/36 probability (97.22%) that the machine is telling the truth and therefore the sun has exploded. The Bayesian is factoring in outside facts and information to improve the accuracy of the probability model. He says "Either the machine rolls 6-6 (a 1/36 probability, or 2.77%) or the sun has exploded (an aparently far less likely scenario). Given the comparison, the Bayesian believes it is MORE probable that the machine rolled 6-6 than the sun exploded, given the relative probabilities. If the latter is a 1 in a million chance (0.000001%), it is 2,777,777 times more likely that the machine rolled 6-6 than the sun exploded.
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Unsurprisingly, the comments have been polluted by Yuddites. Kill yourselves, retards.{{unsigned ip|96.24.247.242}}
To borrow a demonstration/explanation technique from the Monty Hall problem, if the machine told you a coin flip was heads, that would be 50% chance of occuring while a 2.7% chance of the machine lying, the probabilities would clearly suggest that the machine was more likely to be telling the truth. Whereas if the machine said that 100 coin flips had all come up heads (7.88x10^-31%). Is it more likely that 100 coin flips all came up heads or is it more likely the machine is lying? What about 1000 coin flips? or 1,000,000? I think the question is, whether one could assign a probability to the sun exploding. Also, I think they could have avoided the whole thing by asking the machine a second time and see what it answered. [[User:TheHYPO|TheHYPO]] ([[User talk:TheHYPO|talk]]) 19:09, 12 November 2012 (UTC)
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Another source of explanation: http://stats.stackexchange.com/questions/43339/whats-wrong-with-xkcds-frequentists-vs-bayesians-comic --[[User:JakubNarebski|JakubNarebski]] ([[User talk:JakubNarebski|talk]]) 20:12, 12 November 2012 (UTC)
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I don't like the explanation at all. Some of the discussion posts give a good view on this. I'd like to share my thought about the last panel, though. The page reads as if the punch line is about the fact that you cannot spend the money if the sun was going to explode; but why does the bayesian propose this bet and not the frequentist - no reason for this. I think there is a better explanation for this panel: there are several proofs that bayesian probabilities result in "rational" behaviour: They state that if you act according to bayes' rule you cannot be cheated in betting. [[Special:Contributions/108.162.254.179|108.162.254.179]] 17:11, 6 March 2014 (UTC)
  
The P-value really has nothing to do with it.  If I think that there is a 35/36 chance that the sun has exploded, then I should we willing to take any bet that the sun has exploded with better than 1:35 odds.  For example, if someone bets me that the sun has exploded in which they will pay me $2 if the sun has exploded and I will pay them $35 if it hasn't, then based on my belief that the sun has exploded with 35/36 probability, then my expected value for this bet is 2*35/36 - 35 * 1/36 = 35/36 dollars and I will take this bet.  Clearly I would also take a bet with 1:1 odds - my estimated expected value in the proposed bet in the comic would be 50*35/36 - 50 * 1/36 = $49 (approximately), and I would for sure take this bet.  The Bayesian on the other hand has a much lower belief that the sun has exploded because he takes into account the prior probability of the sun exploding, so he would take the reverse side of the bet. The difference is that the Bayesian uses prior probabilities in computing his belief in an event, whereas frequentists do not believe that you can put prior probabilities on events in the real world.  Also note that this comic has nothing to do with whether people would die if the sun went nova - the comic is titled "Frequentists vs Bayesians" and is about the difference between these two approaches. {{unsigned|171.64.68.120}}
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The last panel may refer to Nate Sliver's view expressed in his book {{w|The Signal and the Noise}} that if one believes one's prediction to be true one should be confident to bet on it. --[[User:Troy0|Troy0]] ([[User talk:Troy0|talk]]) 18:46, 6 July 2014 (UTC)
 
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The Labyrinth reference reminds me of an old Doctor Who episode (Pyramid of Mars), where the Doctor is also faced with a truthful and untruthful set of guards. Summarized here: http://tardis.wikia.com/wiki/Pyramids_of_Mars_(TV_story) [[User:Fermax|Fermax]] ([[User talk:Fermax|talk]]) 04:49, 14 November 2012 (UTC)
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Revision as of 18:46, 6 July 2014

Something should be added about the prior probability of the sun going nova, as that is the primary substantive point. "The neutrino detector is evidence that the Sun has exploded. It's showing an observation which is 35 times more likely to appear if the Sun has exploded than if it hasn't (likelihood ratio of 35:1). The Bayesian just doesn't think that's strong enough evidence to overcome the prior odds, i.e., after multiplying the prior odds by 35 they still aren't very high." - http://lesswrong.com/r/discussion/lw/fe5/xkcd_frequentist_vs_bayesians/ 209.65.52.92 23:51, 9 November 2012 (UTC)

Note: taking that bet would be a mistake. If the Bayesian is right, you're out $50. If he's wrong, everyone is about to die and you'll never get to spend the winnings. Of course, this meta-analysis is itself a type of Bayesian thinking, so Dunning-Kruger Effect would apply. - Frankie (talk) 13:50, 9 November 2012 (UTC)

You don't think you could spend fifty bucks in eight minutes? ;-) (PS: wikipedia is probably a better link than lmgtfy: Dunning-Kruger effect) -- IronyChef (talk) 15:35, 9 November 2012 (UTC)

Randall has referenced the Labyrinth guards before: xkcd 246:Labyrinth puzzle. Plus he has satirized p<0.05 in xkcd 882:Significant--Prooffreader (talk) 15:59, 9 November 2012 (UTC)

A bit of maths. Let event N be the sun going nova and event Y be the detector giving the answer "Yes". The detector has already given a positive answer so we want to compute P(N|Y). Applying the Bayes' theorem:

P(N|Y) = P(Y|N) * P(N) / P(Y)
P(Y|N) = 1
P(N) = 0.0000....
P(Y|N) * P(N) = 0.0000...
P(Y) = p(Y|N)*P(N) + P(Y|-N)*P(-N)
P(Y|-N) = 1/36
P(-N) = 0.999999...
P(Y) = 0 + 1/36 = 1/36
P(N|Y) = 0 / (1/36) = 0

Quite likely it's not entirely correct. Lmpk (talk) 16:22, 9 November 2012 (UTC)

Here's what I get for the application of Bayes' Theorem:

P(N|Y) = P(Y|N) * P(N) / P(Y)
= P(Y|N) * P(N) / [P(Y|N) * P(N) + P(Y|~N) * P(~N)]
= 35/36 * P(N) / [35/36 * P(N) + 1/36 * (1 - P(N))]
= 35 * P(N) / [35 * P(N) - P(N) + 1]
< 35 * P(N)
= 35 * (really small number)

So, if you believe it's extremely unlikely for the sun to go nova, then you should also believe it's unlikely a Yes answer is true.

I wouldn't say the comic is about election prediction models. It's about a long-standing dispute between two different schools of statisticians, a dispute that began before Nate Silver was born. It's possible that the recent media attention for Silver and his ilk inspired this subject, but it's the kind of geeky issue Randall would typically take on in other circumstances too. MGK (talk) 19:44, 9 November 2012 (UTC)

I agree - this is not directed at the US-presidential election. I also want to add, that Bayesian btatistics assumes that parameters of distributions (e.g. mean of gaussian) are also random variables. These random variables have prior distributions - in this case p(sun explodes). The Bayesian statistitian in this comic has access to this prior distribution and so has other estimates for an error of the neutrino detector. The knowlege of the prior distribution is somewhat considered a "black art" by other statisticians.

My personal interpretation of the "bet you $50 it hasn't" reply is in the case of the sun going nova, no one would be alive to ask the neutrino detector, the probability of the sun going nova is always 0. Paps

Yes, you would be able to ask. While neutrinos move almost at speed of light, the plasma of the explosion is significally slower, 10% of speed of light tops. You will have more that hour to ask. (Note that technically, sun can't go nova, because nova is white dwarf with external source of hydrogen. It can (and will), however, go supernova, which I assume is what Randall means.) -- Hkmaly (talk) 09:19, 12 November 2012 (UTC)
Our sun will not go supernova, as it has insufficient mass. It will slowly become hotter, rendering Earth uninhabitable in a few billion years. In about 5 billion years it will puff up into a red giant, swallowing the inner planets. After that, it will gradually blow off its lighter gasses, eventually leaving behind the core, a white dwarf. 50.0.38.245 01:58, 15 November 2012 (UTC)
Please don't edit others' comments on talk pages; it's considered quite rude. On a talk page, discourse is meant to be conducted, by editors for the betterment of the article. For constructive discourse to occur, a person's words must be left in tact. The act of censorship hurts the common goal of betterment. Per Wikipedia, the authoritative source on how a wiki works best: "you should not edit or delete the comments of other editors without their permission." lcarsos_a (talk) 17:38, 13 November 2012 (UTC) Note: much of this conversation has been removed at the request of the authors.

I think the explanation is wrong or otherwise lacking in its explanation: The P-value is not the entire problem with the frequentist's viewpoint (or alternatively, the problem with the p-value hasn't been explained). The Frequentist has looked strictly at a two case scenario: Either the machine rolls 6-6 and is lying, or it doesn't rolls 6-6 and it is telling the truth. Therefore, there is a 35/36 probability (97.22%) that the machine is telling the truth and therefore the sun has exploded. The Bayesian is factoring in outside facts and information to improve the accuracy of the probability model. He says "Either the machine rolls 6-6 (a 1/36 probability, or 2.77%) or the sun has exploded (an aparently far less likely scenario). Given the comparison, the Bayesian believes it is MORE probable that the machine rolled 6-6 than the sun exploded, given the relative probabilities. If the latter is a 1 in a million chance (0.000001%), it is 2,777,777 times more likely that the machine rolled 6-6 than the sun exploded. To borrow a demonstration/explanation technique from the Monty Hall problem, if the machine told you a coin flip was heads, that would be 50% chance of occuring while a 2.7% chance of the machine lying, the probabilities would clearly suggest that the machine was more likely to be telling the truth. Whereas if the machine said that 100 coin flips had all come up heads (7.88x10^-31%). Is it more likely that 100 coin flips all came up heads or is it more likely the machine is lying? What about 1000 coin flips? or 1,000,000? I think the question is, whether one could assign a probability to the sun exploding. Also, I think they could have avoided the whole thing by asking the machine a second time and see what it answered. TheHYPO (talk) 19:09, 12 November 2012 (UTC)

Another source of explanation: http://stats.stackexchange.com/questions/43339/whats-wrong-with-xkcds-frequentists-vs-bayesians-comic --JakubNarebski (talk) 20:12, 12 November 2012 (UTC)

The P-value really has nothing to do with it. If I think that there is a 35/36 chance that the sun has exploded, then I should we willing to take any bet that the sun has exploded with better than 1:35 odds. For example, if someone bets me that the sun has exploded in which they will pay me $2 if the sun has exploded and I will pay them $35 if it hasn't, then based on my belief that the sun has exploded with 35/36 probability, then my expected value for this bet is 2*35/36 - 35 * 1/36 = 35/36 dollars and I will take this bet. Clearly I would also take a bet with 1:1 odds - my estimated expected value in the proposed bet in the comic would be 50*35/36 - 50 * 1/36 = $49 (approximately), and I would for sure take this bet. The Bayesian on the other hand has a much lower belief that the sun has exploded because he takes into account the prior probability of the sun exploding, so he would take the reverse side of the bet. The difference is that the Bayesian uses prior probabilities in computing his belief in an event, whereas frequentists do not believe that you can put prior probabilities on events in the real world. Also note that this comic has nothing to do with whether people would die if the sun went nova - the comic is titled "Frequentists vs Bayesians" and is about the difference between these two approaches. 171.64.68.120 (talk) (please sign your comments with ~~~~)

The Labyrinth reference reminds me of an old Doctor Who episode (Pyramid of Mars), where the Doctor is also faced with a truthful and untruthful set of guards. Summarized here: http://tardis.wikia.com/wiki/Pyramids_of_Mars_(TV_story) Fermax (talk) 04:49, 14 November 2012 (UTC)

This is actually an example of the Base rate fallacy. --71.199.125.210 04:04, 19 November 2012 (UTC)

People have gone over this already, but just to be a bit more explicit: Let NOVA be the event that there was a nova, and let YES be the event that the detector responds "Yes" to the question "Did the sun go nova?" What we want is P(NOVA|YES)=P(YES|NOVA)*P(NOVA)/P(YES) Suppose P(NOVA)=p is the prior probability of a nova. Then P(YES|NOVA)=35/36, P(NOVA)=p, and P(YES)=p*35/36+(1-p)*1/36=1/36+34/36 So then P(NOVA|YES)=35p/(1+34p). If p is small, then P(NOVA|YES) is also small. In particular, the Bayesian statistician wins his bet at 1:1 odds if p<1/36, which is probably the case. If the Bayesian statistician wants 95% confidence that he'll win his bet, then he needs p<1/666. =P


It's cute to attempt to connect this to the U.S. presidential election, but it's far likelier that it's a reference to Enrico Fermi taking bets at the Trinity test site as to whether or not the first atomic bomb would cause a chain reaction that would ignite the entire atmosphere and destroy the planet. I'll bet you $50 it is. 71.229.88.206 21:29, 7 March 2013 (UTC)

Unsurprisingly, the comments have been polluted by Yuddites. Kill yourselves, retards. 96.24.247.242 (talk) (please sign your comments with ~~~~)

I don't like the explanation at all. Some of the discussion posts give a good view on this. I'd like to share my thought about the last panel, though. The page reads as if the punch line is about the fact that you cannot spend the money if the sun was going to explode; but why does the bayesian propose this bet and not the frequentist - no reason for this. I think there is a better explanation for this panel: there are several proofs that bayesian probabilities result in "rational" behaviour: They state that if you act according to bayes' rule you cannot be cheated in betting. 108.162.254.179 17:11, 6 March 2014 (UTC)

The last panel may refer to Nate Sliver's view expressed in his book The Signal and the Noise that if one believes one's prediction to be true one should be confident to bet on it. --Troy0 (talk) 18:46, 6 July 2014 (UTC)

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