Talk:356: Nerd Sniping

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The 1/2 ohm resistance between adjacent nodes is actually well known.
 
The 1/2 ohm resistance between adjacent nodes is actually well known.
 
[[User:Divad27182|Divad27182]] ([[User talk:Divad27182|talk]]) 05:05, 5 October 2012 (UTC)
 
[[User:Divad27182|Divad27182]] ([[User talk:Divad27182|talk]]) 05:05, 5 October 2012 (UTC)
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Solution here as well: http://mathworld.wolfram.com/news/2004-10-13/google/ [[User:Potie15|Potie15]] ([[User talk:Potie15|talk]]) 03:50, 18 March 2013 (UTC)

Revision as of 03:50, 18 March 2013

Just because the problem contains an infinite series (or parallel) doesn't mean that it's unsolvable. It's tricky, certainly, and getting the "true" answer involves some rather heavy math, but it's not impossible. Indeed, Google shows that it's already been answered. 76.122.5.96 20:42, 20 September 2012 (UTC)

I've always had an issue with this problem for one simple reason. In an infinite set of resistors, there is no space to apply a charge, thus there is no resistance. Ohm's law states Resistance = Voltage / I(current). So, in a system where there is no current (creating a divide by zero error), and there is no voltage (no change in electron work capacity, because we don't have a way to excite the electrons, because there is no power) Resistance is incalculable. lcarsos (talk) 22:22, 20 September 2012 (UTC)

We live in 3 dimensions, just place a battery above the grid with wires going to the 2 points. --84.197.34.154 22:59, 24 October 2012 (UTC)

Not everybody does... --FlatlandDweller 11:08, 15 November 2012 (UTC)

This problem is "unsolvable" only if you try to just use the basic methods for finite networks. There is a page on this at http://mathpages.com/home/kmath668/kmath668.htm that reports that the cited points have a resistance of 4/pi - 1/2 ohms (.773234... ohms). The 1/2 ohm resistance between adjacent nodes is actually well known. Divad27182 (talk) 05:05, 5 October 2012 (UTC)

Solution here as well: http://mathworld.wolfram.com/news/2004-10-13/google/ Potie15 (talk) 03:50, 18 March 2013 (UTC)

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