Difference between revisions of "Talk:849: Complex Conjugate"

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Actually multiplying complex number (x + iy) by its complex conjugate (x - iy) does not "remove" imaginary part, but calculate square of absolute value of complex number, (x^2 + y^2).  BTW. in quantum physics the wavefunction is complex valued, and its absolute value is probability density (a real valued function). --[[User:JakubNarebski|JakubNarebski]] ([[User talk:JakubNarebski|talk]]) 00:57, 18 December 2012 (UTC)
 
Actually multiplying complex number (x + iy) by its complex conjugate (x - iy) does not "remove" imaginary part, but calculate square of absolute value of complex number, (x^2 + y^2).  BTW. in quantum physics the wavefunction is complex valued, and its absolute value is probability density (a real valued function). --[[User:JakubNarebski|JakubNarebski]] ([[User talk:JakubNarebski|talk]]) 00:57, 18 December 2012 (UTC)
  
I got hit in the face with my complex conjugate and lost an eye.
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I got hit in the face with my complex conjugate and lost an eye. {{unsigned ip|108.162.238.114}}

Revision as of 14:56, 4 July 2014

Actually multiplying complex number (x + iy) by its complex conjugate (x - iy) does not "remove" imaginary part, but calculate square of absolute value of complex number, (x^2 + y^2). BTW. in quantum physics the wavefunction is complex valued, and its absolute value is probability density (a real valued function). --JakubNarebski (talk) 00:57, 18 December 2012 (UTC)

I got hit in the face with my complex conjugate and lost an eye. 108.162.238.114 (talk) (please sign your comments with ~~~~)