Editing 1201: Integration by Parts

Jump to: navigation, search

Warning: You are not logged in. Your IP address will be publicly visible if you make any edits. If you log in or create an account, your edits will be attributed to your username, along with other benefits.

The edit can be undone. Please check the comparison below to verify that this is what you want to do, and then save the changes below to finish undoing the edit.
Latest revision Your text
Line 9: Line 9:
 
==Explanation==
 
==Explanation==
 
{{w|Integration by parts}} is an integration strategy that is used to evaluate difficult {{w|integrals}} by trying to find simpler integrals derived from the original. It is commonly a source of confusion or irritation for students when they first learn it, due to the fact that there is really no way to accurately predict the proper u/dv separation just by looking at an integral. Integration by parts requires patience, trial and error, and experience.
 
{{w|Integration by parts}} is an integration strategy that is used to evaluate difficult {{w|integrals}} by trying to find simpler integrals derived from the original. It is commonly a source of confusion or irritation for students when they first learn it, due to the fact that there is really no way to accurately predict the proper u/dv separation just by looking at an integral. Integration by parts requires patience, trial and error, and experience.
 +
 +
Integration by parts derives from the formula for differentiating a product : ''d(u.v) = u.dv + v.du'', hence ''u.dv = d(u.v) - v.du'', and the equation can then be transposed to the integrals: '''''∫'''u.dv = [u.v] - '''∫'''v.du''. This simplifies the problem if ''u'' simplifies when differentiated, and/or ''v'' simplifies when integrated.
  
 
[[Randall]] shows a somewhat complicated math problem and, in an attempt to "help", simplifies it into a more compact integral. This is the first part of performing integration by parts, which involves the guessing. Having gotten it into integration by parts format, he then leaves without describing the actual solution. The general integral '''''∫'''(u dv)'' is equal to ''uv - '''∫'''(v du)'', and this is the more tedious part of the math and where problems will arise if you picked the wrong u and dv at the beginning. The narrator makes a point of leaving here, so we can't ask for help or complain if the choice of u and dv was wrong.
 
[[Randall]] shows a somewhat complicated math problem and, in an attempt to "help", simplifies it into a more compact integral. This is the first part of performing integration by parts, which involves the guessing. Having gotten it into integration by parts format, he then leaves without describing the actual solution. The general integral '''''∫'''(u dv)'' is equal to ''uv - '''∫'''(v du)'', and this is the more tedious part of the math and where problems will arise if you picked the wrong u and dv at the beginning. The narrator makes a point of leaving here, so we can't ask for help or complain if the choice of u and dv was wrong.

Please note that all contributions to explain xkcd may be edited, altered, or removed by other contributors. If you do not want your writing to be edited mercilessly, then do not submit it here.
You are also promising us that you wrote this yourself, or copied it from a public domain or similar free resource (see explain xkcd:Copyrights for details). Do not submit copyrighted work without permission!

To protect the wiki against automated edit spam, we kindly ask you to solve the following CAPTCHA:

Cancel | Editing help (opens in new window)