Editing 1276: Angular Size
Warning: You are not logged in. Your IP address will be publicly visible if you make any edits. If you log in or create an account, your edits will be attributed to your username, along with other benefits.
The edit can be undone.
Please check the comparison below to verify that this is what you want to do, and then save the changes below to finish undoing the edit.
Latest revision | Your text | ||
Line 12: | Line 12: | ||
London's {{w|M25 motorway}} is around 60 kilometers (35 miles) across, a {{w|soccer field}} is about 100 meters long (109 yards), a {{w|Table tennis table|ping pong table}} is 274 centimeters long (9 feet), a {{w|laptop}} is about 35 centimeters across (13.75 inches), the {{w|tilde}} symbol on a keyboard is about 5 millimeters long (197 mils), and a cell of ''{{w|Escherichia coli|E. coli}}'' is about 2 micrometers long (78.75 millionths of an inch). | London's {{w|M25 motorway}} is around 60 kilometers (35 miles) across, a {{w|soccer field}} is about 100 meters long (109 yards), a {{w|Table tennis table|ping pong table}} is 274 centimeters long (9 feet), a {{w|laptop}} is about 35 centimeters across (13.75 inches), the {{w|tilde}} symbol on a keyboard is about 5 millimeters long (197 mils), and a cell of ''{{w|Escherichia coli|E. coli}}'' is about 2 micrometers long (78.75 millionths of an inch). | ||
β | A simple {{w|Intercept theorem|formula}} can be used to find the size on earth of a celestial object when the size of | + | A simple {{w|Intercept theorem|formula}} can be used to find the size on earth of a celestial object when the size of and distance to the object is known. This is done by taking the radius of the earth, multiplying by the diameter of the object, and dividing by the distance to the object from the center of the earth. |
The space objects referenced in the panels are: | The space objects referenced in the panels are: |