Difference between revisions of "Talk:1562: I in Team"
Cwallenpoole (talk | contribs) m |
(hmm) |
||
Line 12: | Line 12: | ||
::: No. There is no evidence that pi includes an offset of pi. | ::: No. There is no evidence that pi includes an offset of pi. | ||
+ | |||
+ | :::: ''finite'' sequence. the kate bush conjecture is unproven. | ||
There is no I in team, but there is meat... blessed meat :::Simpson drool:: | There is no I in team, but there is meat... blessed meat :::Simpson drool:: |
Revision as of 11:48, 10 August 2015
There is no I in team, but there is an M and an E.162.158.56.215 08:26, 10 August 2015 (UTC)
Check it out! there's "l" in "vowels"! --141.101.89.222 08:51, 10 August 2015 (UTC)
<sarcasm>There is an (annagram of) Randal in "People who don't understand how a proverb works" </sarcasm> No, seriously this is just cueball being a smart-ass. --162.158.91.230 08:53, 10 August 2015 (UTC)
There's no I in team, but there is an I in pie; there's an I in meat pie and meat is an anagram of team, so...
- There's a 999999 in pi.
- Doesn't pi contain every possible number sequence though? 162.158.91.235 11:17, 10 August 2015 (UTC)
- No. There is no evidence that pi includes an offset of pi.
- finite sequence. the kate bush conjecture is unproven.
There is no I in team, but there is meat... blessed meat :::Simpson drool::