Talk:216: Romantic Drama Equation

Explain xkcd: It's 'cause you're dumb.
Revision as of 21:38, 21 December 2013 by (talk)
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This can't be right, even at 50/50, the number of gay pairings far outnumbers the number of straight pairings. 20:10, 28 February 2013 (UTC) Moved from article page

Not quite. Consider a cast of 4 with 2 male (A, B) and 2 female (C, D). Possible gay pairings - 2 (A-B and C-D). Possible straight pairings - 4 (A-C, A-D, B-C, B-D) (talk) (please sign your comments with ~~~~)
He says for large casts. For 2000 cast members, with 1000 of each gender, the gay couplings comes out at 999,000 and straight at 1,000,000. Presumably this is the small cross over the diagram alludes to. If you substitute x = n/2 into the equations, then you get (n^2-2n)/4 for the gay combinations and n^2/4 for the straight combinations, so for gender balanced cast size of n, the straight combinations outnumber the gay by n/2 (talk) (please sign your comments with ~~~~)

There is a typo in his formula for gay casts. The + should be a -.