Difference between revisions of "Talk:2322: ISO Paper Size Golden Spiral"
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The explanation says that the A series "side lengths shrink by a factor of the square root of two" but that's not true. The width of A(n+1) is half the length of A(n) as depicted. The sqrt(2) ratio referenced is between the length and width of any one piece of paper.[[Special:Contributions/172.69.62.124|172.69.62.124]] 15:35, 19 June 2020 (UTC) | The explanation says that the A series "side lengths shrink by a factor of the square root of two" but that's not true. The width of A(n+1) is half the length of A(n) as depicted. The sqrt(2) ratio referenced is between the length and width of any one piece of paper.[[Special:Contributions/172.69.62.124|172.69.62.124]] 15:35, 19 June 2020 (UTC) | ||
| + | :The side lengths do shrink by a factor of sqrt(2): the width of A(n) is sqrt(2) times the width of A(n+1), the length of A(n) is sqrt(2) times the length of A(n+1). Your statement that "the width of A(n+1) is half the length of A(n)" is also true, but it does not contradict that each step in the A-series shrinks the sides by a factor of sqrt(2). [[User:Zmatt|Zmatt]] ([[User talk:Zmatt|talk]]) 16:09, 19 June 2020 (UTC) | ||
Fixed it [[Special:Contributions/162.158.74.61|162.158.74.61]] 15:43, 19 June 2020 (UTC) | Fixed it [[Special:Contributions/162.158.74.61|162.158.74.61]] 15:43, 19 June 2020 (UTC) | ||
Hi ! How come 11/8.5 = Pi/4 ? First one is more thant 1, second one is less than one... Although Pi/4 and 8.5/11 (or the reverse) are pretty similar, as usual in "let's annoy mathematicians" Randall's style... | Hi ! How come 11/8.5 = Pi/4 ? First one is more thant 1, second one is less than one... Although Pi/4 and 8.5/11 (or the reverse) are pretty similar, as usual in "let's annoy mathematicians" Randall's style... | ||
Revision as of 16:09, 19 June 2020
It annoys me that the hover text says 11/8.5 = pi/4, when 8.5/11≈0.77272727272 and pi/4≈0.78539816339. Claiming 8.5/11 equals pi/4 would be a much more beleiveable lie. 162.158.79.37 15:29, 19 June 2020 (UTC)
The explanation says that the A series "side lengths shrink by a factor of the square root of two" but that's not true. The width of A(n+1) is half the length of A(n) as depicted. The sqrt(2) ratio referenced is between the length and width of any one piece of paper.172.69.62.124 15:35, 19 June 2020 (UTC)
- The side lengths do shrink by a factor of sqrt(2): the width of A(n) is sqrt(2) times the width of A(n+1), the length of A(n) is sqrt(2) times the length of A(n+1). Your statement that "the width of A(n+1) is half the length of A(n)" is also true, but it does not contradict that each step in the A-series shrinks the sides by a factor of sqrt(2). Zmatt (talk) 16:09, 19 June 2020 (UTC)
Fixed it 162.158.74.61 15:43, 19 June 2020 (UTC)
Hi ! How come 11/8.5 = Pi/4 ? First one is more thant 1, second one is less than one... Although Pi/4 and 8.5/11 (or the reverse) are pretty similar, as usual in "let's annoy mathematicians" Randall's style...
