# 953: 1 to 10

1 to 10 |

Title text: If you get an 11/100 on a CS test, but you claim it should be counted as a 'C', they'll probably decide you deserve the upgrade. |

## [edit] Explanation

The binary numeral system refers to a counting system in base-2, which uses only the digits 0 and 1, as opposed to the more familiar base-10 decimal system, which uses the digits 0 through 9. In this case, the scale of 1 to 10 is using binary, so in decimal it would be a scale of 1 to 2. Since 4 in binary is "100" it doesn't fit into the range "1" to "10" in a binary system. And Megan doesn't even know the number "4" because she's only working on the binary system, this character does not exist for her.

It is also possible that Megan is using base-3, which also doesn't use a '4' but counts 1, 2, 10, etc. Base-4 also doesn't have a number '4' in it, despite having a '4' in its name; it counts 1, 2, 3, 10, etc.

The title text uses a similar joke. Since test scores are usually written as either a letter grade or a percentage, 11 correct questions out of 100 would be a failing score in decimal notation. However, 11/100 in binary translates to 3/4 in decimal, which would be 75%, accepted in most classes as a 'C' grade.

Another option is to claim your grade (11) in hexadecimal which would give you a 'B'.

## [edit] Transcript

- Megan: On a scale of 1 to 10, how likely is it that this question is using Binary?
- Cueball: ...4?
- Megan: What's a 4?

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# Discussion

One of correct answers is P = 1 + 1 - |sgn(10 - 1 - 1)|

(|x| is absolute value of x, sgn(x) is 1 when x > 0, 0 when x = 0, and -1 when x < 0)

If 10 = 1 + 1, then P = 10 - |sgn(0)| = 10 - |0| = 10

If 10 > 1 + 1, then P = 1 + 1 - |sgn(10 - 1 - 1)| = 1 + 1 - |1| = 1

If 10 < 1 + 1, then P = 1 + 1 - |sgn(10 - 1 - 1)| = 1 + 1 - |-1| = 1

So P is 10 iif the question was is in binary, and 1 iif it was not in binary.

93.73.186.104 16:26, 6 February 2013 (UTC)

- The absolute value is unnecessary. When is 10 ever less than 1+1?108.162.219.202 20:28, 3 January 2014 (UTC)

I don't think the explanation is right, I mean i don't know binary but i don't think the joke is that he's saying a 4 as in 100% Lackadaisical (talk) 00:23, 7 November 2013 (UTC)

- A 4 is not 100%, but a 3/4 is always 75%. 108.162.212.206 22:47, 26 January 2014 (UTC)
- Actually, my comment was in reference to this: "Since 4 in binary is "100" (one-zero-zero) the joke is that it is 100% likely that the question is binary -- or it could simply be 4 of 10 - which means that the question has evolved into recursive ambiguity. Also, the person asking the question does not know what a 4 is since there is no 4 in binary." The problem I had with it was taken care of in a previous edit (The quote was taken from the 31 December 2013 edit.)--Lackadaisical (talk) 22:03, 26 March 2015 (UTC)

1.(1) is the best answer I've got Halfhat (talk) 11:53, 5 April 2014 (UTC)

"How likely" it is? As everyone knows, "every base is base 10", since every base number in its own numbering system is written as "10" (2 is 10 in binary, 16 is 10 in hex and so on). So that question could be in EVERY number system possible. I suppose the probability is then 1 over an infinite number of systems, then very unlikely, so I'd say (as 0 is not in the range of possible answers) the answer is 1. Which, incidentally, is also an acceptable answer for every system. If we want instead to take into account that Megan doesn't know what a 4 is, the possibilities are only base 2, 3 and 4. So the likeliness is 1/3, which corresponds anyway to 1 in those number systems. --108.162.229.31 14:05, 3 June 2014 (UTC)

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