Editing Talk:2649: Physics Cost-Saving Tips

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Is it worth mentioning the L and omega displayed in the first illustration are in conflicting directions (not following the {{w|right hand rule}}…)?[[Special:Contributions/172.70.210.145|172.70.210.145]]
 
Is it worth mentioning the L and omega displayed in the first illustration are in conflicting directions (not following the {{w|right hand rule}}…)?[[Special:Contributions/172.70.210.145|172.70.210.145]]
 
:How sinister! [[Special:Contributions/172.70.91.80|172.70.91.80]] 19:28, 23 July 2022 (UTC)
 
:How sinister! [[Special:Contributions/172.70.91.80|172.70.91.80]] 19:28, 23 July 2022 (UTC)
:Done, including a video proving Randall is right-handed, so that can't be the reason. [[Special:Contributions/172.70.206.163|172.70.206.163]] 07:45, 24 July 2022 (UTC)
 
  
 
I disagree with the calculation of the energy of the ²He filled balloon: ²He -> H + H + 1.25MeV (Wikipedia). One Balloon is approx. 30-40l, i.e. approx 2 moles = 2 Avogadro Number = 1.2e24 Atoms of ²He. This means 1.2e24*1.25MeV = 1.9E24MeV = 3e11J = 71 ton of TNT (@4.2e9J/ ton of TNT (Wikipedia)). That is much less than a kiloton of TNT, but probably above the limit for recreational fireworks. The balloon might pop, too.
 
I disagree with the calculation of the energy of the ²He filled balloon: ²He -> H + H + 1.25MeV (Wikipedia). One Balloon is approx. 30-40l, i.e. approx 2 moles = 2 Avogadro Number = 1.2e24 Atoms of ²He. This means 1.2e24*1.25MeV = 1.9E24MeV = 3e11J = 71 ton of TNT (@4.2e9J/ ton of TNT (Wikipedia)). That is much less than a kiloton of TNT, but probably above the limit for recreational fireworks. The balloon might pop, too.

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