Difference between revisions of "Talk:1935: 2018"
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This is easy! Don't factor it - just subtract 4 repeatedly. If you end up at 0, it's divisible. If you end up at 1, 2, or 3, it's not. -- 17:55, 29 December 2017 (UTC) | This is easy! Don't factor it - just subtract 4 repeatedly. If you end up at 0, it's divisible. If you end up at 1, 2, or 3, it's not. -- 17:55, 29 December 2017 (UTC) | ||
− | The | + | == Title text explanation mis-read == |
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+ | Explanation of title text is incorrect: | ||
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+ | "The title text refers to calculating the date of Christmas; again, this is a trivial exercise, because Christmas is always December 25." | ||
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+ | Title text states 'day of Christmas', not 'date...'. The day changes each year and so does require calculation. |
Revision as of 18:04, 29 December 2017
This is easy! Don't factor it - just multiply by 25 and if that ends in two zeros, but not four zeros then it's a leap year, at least most of the time.....17:25, 29 December 2017 (UTC)
This is easy! Don’t factor it - just convert it into a binary and look at the 2 least significant bits. If they are 00 the number is multiple of four. —172.69.33.35 17:37, 29 December 2017 (UTC)
This is easy! Don't factor it - just subtract 4 repeatedly. If you end up at 0, it's divisible. If you end up at 1, 2, or 3, it's not. -- 17:55, 29 December 2017 (UTC)
Title text explanation mis-read
Explanation of title text is incorrect:
"The title text refers to calculating the date of Christmas; again, this is a trivial exercise, because Christmas is always December 25."
Title text states 'day of Christmas', not 'date...'. The day changes each year and so does require calculation.