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− | Asserting that the programmers' algorithms truncated to three decimal digits is an unsupported and unnecessary extrapolation. Most floating-point implementations use binary, not decimal, and 19.999099979 ''looks'' very much like a rounding error in binary floating-point that has accumulated over several operations. [[User:Daddy|Daddy]] ([[User talk:Daddy|talk]]) 12:39, 29 April 2013 (UTC)
| + | How to get free robux in roblox https://freerobuxtips.com first time i have no idea how to generator robux. |
− | :Fixed. [[User:Xhfz|Xhfz]] ([[User talk:Xhfz|talk]]) 22:57, 16 August 2013 (UTC)
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− | The "not good at math" might be too harsh, if they've (tried to) read the floating point spec. Depending on precision and rounding regime and order of operations, I could easily imagine the "equation" to be true ... and therefore a test that you were rounding "properly", even when it wasn't intuitive.
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− | The third bullet-point above needs changing... (9^2+(19^2/22))=97.4090909091 which is close to pi to the fourth power, so it should be (as noted in the text) (9^2+(19^2/22))^1/4 [[User:Squirreltape|Squirreltape]] ([[User talk:Squirreltape|talk]]) 19:27, 25 February 2014 (UTC)
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− | :Actually, in-case you didn't notice, it says "∜(9² + 19²/22)", not just the sum on its own. I checked the sum on my calculator, and it is equal to what the page is saying. "∜(9² + 19²/22)" means "4th root of (9^2+19^2/22)" (What the title text is saying), or on Windows Calculator, "(9^2+19^2/22) yroot(4)" (Basically what the sum is saying). So, the 3rd bullet point is correct. --[[User:Katavschi|Katavschi]] ([[User talk:Katavschi|talk]]) 22:48, 23 April 2014 (UTC)
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− | It says above that (π + 20)^i ≈ -i, but this should be (π + 20)^i ≈ -1. Proof: π + 20 ≈ e^π => (π + 20)^i ≈ (e^π)^i = e^(πi) = -1.
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− | The ACM competitions are famous for being under tight time pressure. Making your own team waste time would absolutely get you kicked out (and make enemies) [[User:Danshoham|Mountain Hikes]] ([[User talk:Danshoham|talk]]) 04:40, 23 September 2015 (UTC)
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− | ;"If they thought about the mathematics"
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− | hm, are you saying it is obvious that e^ pi - pi is not 20? How would you know without approximating it? The sum of two irrationals is not necessarily irrational. [[Special:Contributions/162.158.34.194|162.158.34.194]] 01:58, 26 October 2015 (UTC)
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− | :approximate e^pi using slightly bigger numbers than e and pi (say e: 2.7183 and pi: 3.1416) and subtract a value that is slightly smaller than pi (say 3.1415). The result is less than 20 and a upper limit for e^pi - pi [[Special:Contributions/141.101.93.49|141.101.93.49]] 19:59, 22 August 2016 (UTC)
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− | the title text was close; the real identity is e^(π - 2) = π [[Special:Contributions/173.245.52.165|173.245.52.165]] 05:39, 7 April 2021 (UTC)
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