Difference between revisions of "Talk:1935: 2018"

Explain xkcd: It's 'cause you're dumb.
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(Title text explanation mis-read: new section)
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This is easy! Don't factor it - just subtract 4 repeatedly. If you end up at 0, it's divisible. If you end up at 1, 2, or 3, it's not. -- 17:55, 29 December 2017 (UTC)
 
This is easy! Don't factor it - just subtract 4 repeatedly. If you end up at 0, it's divisible. If you end up at 1, 2, or 3, it's not. -- 17:55, 29 December 2017 (UTC)
  
The calculation of Christmas is trivial{{Citation needed}} it's December 25th. Where as the calculation of Easter is complex ([https://en.wikipedia.org/wiki/Computus]). [[Special:Contributions/172.68.133.18|172.68.133.18]] 18:03, 29 December 2017 (UTC)
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== Title text explanation mis-read ==
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Explanation of title text is incorrect:
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"The title text refers to calculating the date of Christmas; again, this is a trivial exercise, because Christmas is always December 25."
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Title text states 'day of Christmas', not 'date...'. The day changes each year and so does require calculation.

Revision as of 18:04, 29 December 2017

This is easy! Don't factor it - just multiply by 25 and if that ends in two zeros, but not four zeros then it's a leap year, at least most of the time.....17:25, 29 December 2017 (UTC)

This is easy! Don’t factor it - just convert it into a binary and look at the 2 least significant bits. If they are 00 the number is multiple of four. —172.69.33.35 17:37, 29 December 2017 (UTC)

This is easy! Don't factor it - just subtract 4 repeatedly. If you end up at 0, it's divisible. If you end up at 1, 2, or 3, it's not. -- 17:55, 29 December 2017 (UTC)

Title text explanation mis-read

Explanation of title text is incorrect:


"The title text refers to calculating the date of Christmas; again, this is a trivial exercise, because Christmas is always December 25."


Title text states 'day of Christmas', not 'date...'. The day changes each year and so does require calculation.