Editing Talk:2566: Decorative Constants

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:: To the sort of person who (thoughtfully) uses c=1, this feels a bit like saying that the "f" is profound in dist=sqrt[x^2+y^2+(z/f)^2], where of course I've measured xy-distances in miles and z-distances in feet, so f=5280ft/mi. Yes, it's entirely possible to choose different units for different coordinates, and if you're very accustomed to that then the conversion factors can be deeply important for your understanding of the system (and provide extra flexibility in your choice of units: you can easily use "f=1760yd/mi" if you'd prefer). But there's still a very well-defined sense in which sqrt[x^2+y^2+z^2] is the more fundamental equation, and the "f" is an unnecessary complication (however convenient it may be). Whether I'd call it "decorative"... I'm not sure. But I don't see this "f" as profound. [[User:Steuard|Steuard]] ([[User talk:Steuard|talk]]) 17:59, 29 May 2022 (UTC)
 
:: To the sort of person who (thoughtfully) uses c=1, this feels a bit like saying that the "f" is profound in dist=sqrt[x^2+y^2+(z/f)^2], where of course I've measured xy-distances in miles and z-distances in feet, so f=5280ft/mi. Yes, it's entirely possible to choose different units for different coordinates, and if you're very accustomed to that then the conversion factors can be deeply important for your understanding of the system (and provide extra flexibility in your choice of units: you can easily use "f=1760yd/mi" if you'd prefer). But there's still a very well-defined sense in which sqrt[x^2+y^2+z^2] is the more fundamental equation, and the "f" is an unnecessary complication (however convenient it may be). Whether I'd call it "decorative"... I'm not sure. But I don't see this "f" as profound. [[User:Steuard|Steuard]] ([[User talk:Steuard|talk]]) 17:59, 29 May 2022 (UTC)
  
I think the 1/2 in the drag equation is intuitive. I understand that it is technically superfluous, but F=Pd*A and Pd=1/2*rho*u^2 so the 1/2 carries over intuitively. {{unsigned ip|172.70.98.15}}
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I think the 1/2 in the drag equation is intuitive. I understand that it is technically superfluous, but F=Pd*A and Pd=1/2*rho*u^2 so the 1/2 carries over intuitively. {{usigned ip|172.70.98.15}}
 
:Agrees I had this written down in an early version of the explanation but that was edited out. Maybe I will put it in again.--[[User:Kynde|Kynde]] ([[User talk:Kynde|talk]]) 10:44, 12 January 2022 (UTC)
 
:Agrees I had this written down in an early version of the explanation but that was edited out. Maybe I will put it in again.--[[User:Kynde|Kynde]] ([[User talk:Kynde|talk]]) 10:44, 12 January 2022 (UTC)
  

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