Difference between revisions of "User:SqueakSquawk4"
(Baloon nukes) |
(Reply and add noinclude tag sets, and expose original content in them) |
||
| Line 1: | Line 1: | ||
| − | < | + | <noinclude>I have done a bunch of things! I wrote most of explanation for [[2527]], and created (Badly) the page for [[2616]]. I think I screwed that last one up though. I will add more later. |
| + | |||
| + | ---- | ||
Hello people! You are probably looking for how I calculated the yield of a baloon made of Helium-2. Well you're in luck! | Hello people! You are probably looking for how I calculated the yield of a baloon made of Helium-2. Well you're in luck! | ||
| − | Calculation time! (Sorry). Helium 2 has a {{w|Half-life}} of roughly 10^-9 seconds, or one nanosecond, {{w|https://en.wikipedia.org/wiki/Isotopes_of_helium#List_of_isotopes|roughly 10^-9 seconds, or one nanosecond}}, and a mean life of [https://www.omnicalculator.com/chemistry/half-life roughly 1.44 nanoseconds]. For context, light travels at [https://www.google.com/search?q=1+speed+of+light+to+cm%2Fnanosecond roughly 30cm per nanosecond]. This means that on a human scale the energy is released all at once, and we only have to calculate total energy released, and not worry about time taken. | + | Calculation time! (Sorry). </noinclude>Helium 2 has a {{w|Half-life}} of roughly 10^-9 seconds, or one nanosecond, {{w|https://en.wikipedia.org/wiki/Isotopes_of_helium#List_of_isotopes|roughly 10^-9 seconds, or one nanosecond}}, and a mean life of [https://www.omnicalculator.com/chemistry/half-life roughly 1.44 nanoseconds]. For context, light travels at [https://www.google.com/search?q=1+speed+of+light+to+cm%2Fnanosecond roughly 30cm per nanosecond]. This means that on a human scale the energy is released all at once, and we only have to calculate total energy released, and not worry about time taken. |
Helium-2 decays through 99.99% {{w|proton emission}}. For simplicity's sake, we'll call that 100%. Helium-2 is formed from helium-1, helium-1, and 1.25 MegaElectronvolts, or as an equation, 1/1He + 1/1He + 1.25 {{w|MeV}} = 2/2He. It therefore follows that decay from a Helium 2 atom to a helium 1 atom would release 1.25 MeV. | Helium-2 decays through 99.99% {{w|proton emission}}. For simplicity's sake, we'll call that 100%. Helium-2 is formed from helium-1, helium-1, and 1.25 MegaElectronvolts, or as an equation, 1/1He + 1/1He + 1.25 {{w|MeV}} = 2/2He. It therefore follows that decay from a Helium 2 atom to a helium 1 atom would release 1.25 MeV. | ||
| Line 13: | Line 15: | ||
Every atom will create 1.5 MeV of energy, and therefore 364.821 sextillion atoms will create [https://www.google.com/search?client=firefox-b-d&q=364%2C821%2C332%2C070%2C000%2C040%2C000%2C000*1.35 364.821*1.35 sextillion, or 492.5088 sextillion MeV]. Interestingly, this is equal to {{w|Names of large numbers|492.5 nonillion electron volts}}, or {{w|Metric prefix|4.295 MegaYottaElectronvolts}} | Every atom will create 1.5 MeV of energy, and therefore 364.821 sextillion atoms will create [https://www.google.com/search?client=firefox-b-d&q=364%2C821%2C332%2C070%2C000%2C040%2C000%2C000*1.35 364.821*1.35 sextillion, or 492.5088 sextillion MeV]. Interestingly, this is equal to {{w|Names of large numbers|492.5 nonillion electron volts}}, or {{w|Metric prefix|4.295 MegaYottaElectronvolts}} | ||
| − | 492.5088 sextillion MegaElectonvolts is also equal to [https://www.google.com/search?q=492508800000000000000000+MeV+to+Megajoules roughly 78,909 Megajoules,] or [https://www.google.com/search?q=78908.6057416272+Megajoules+to+Tons+of+TNT 18.86 tons of TNT equivalent] | + | 492.5088 sextillion MegaElectonvolts is also equal to [https://www.google.com/search?q=492508800000000000000000+MeV+to+Megajoules roughly 78,909 Megajoules,] or [https://www.google.com/search?q=78908.6057416272+Megajoules+to+Tons+of+TNT 18.86 tons of TNT equivalent]<noinclude> |
This is rather big. but not massively so. The smallest nuclear bomb, the {{w|W54}}, had a yield of between 10 and 1000 {{w|TNT equivalent|tons of TNT}}. The largest conventional bomb, the {{w|GBU-43/B MOAB}}, has a yield of roughly 11 tons. The {{w|M67 grenade}} uses 180 grams of {{w|Composition B|TNT-RDX mixture}}. So while the Helium-2 baloon bomb would be larger than all conventional bombs, it would still be smaller than most nukes. | This is rather big. but not massively so. The smallest nuclear bomb, the {{w|W54}}, had a yield of between 10 and 1000 {{w|TNT equivalent|tons of TNT}}. The largest conventional bomb, the {{w|GBU-43/B MOAB}}, has a yield of roughly 11 tons. The {{w|M67 grenade}} uses 180 grams of {{w|Composition B|TNT-RDX mixture}}. So while the Helium-2 baloon bomb would be larger than all conventional bombs, it would still be smaller than most nukes. | ||
| + | |||
| + | ---- | ||
| + | |||
| + | :That looks great! Sorry I can't talk to you on your talk page, it hasn't been created and I've always been too lazy to make an autoconfimed user. I hope you're okay with the changes in this edit. Do you mind if we subst: this into the collapse box on [[2649]] so it can be cleaned up formatted there? Thanks for looking all that up. [[Special:Contributions/172.70.207.8|172.70.207.8]] 14:37, 24 July 2022 (UTC) | ||
| + | |||
| + | </noinclude><!-- remove all these tags after subst:ing. ~~~~ --> | ||
Revision as of 14:37, 24 July 2022
I have done a bunch of things! I wrote most of explanation for 2527, and created (Badly) the page for 2616. I think I screwed that last one up though. I will add more later.
Hello people! You are probably looking for how I calculated the yield of a baloon made of Helium-2. Well you're in luck!
Calculation time! (Sorry). Helium 2 has a Half-life of roughly 10^-9 seconds, or one nanosecond, roughly 10^-9 seconds, or one nanosecond, and a mean life of roughly 1.44 nanoseconds. For context, light travels at roughly 30cm per nanosecond. This means that on a human scale the energy is released all at once, and we only have to calculate total energy released, and not worry about time taken.
Helium-2 decays through 99.99% proton emission. For simplicity's sake, we'll call that 100%. Helium-2 is formed from helium-1, helium-1, and 1.25 MegaElectronvolts, or as an equation, 1/1He + 1/1He + 1.25 MeV = 2/2He. It therefore follows that decay from a Helium 2 atom to a helium 1 atom would release 1.25 MeV.
A moderately-sized balloon might have a diameter of 12 inches. Some calculations give this a volume of roughyly 14.83 litres (Assuming a spherical balloon). If the balloon is at 1 atmosphere of pressure at 25 degrees celsius, then there would be 0.6058 mol in the balloon, mean that there is 0.6058 * 6.022 × 10^23 atoms, or 364,821,332,070,000,040,000,000 atoms.
To recap, a helium-2 atom decaying results in 1.35 MeV of energy, and there are roughly 364.821 sextillion atoms in a balloon.
Every atom will create 1.5 MeV of energy, and therefore 364.821 sextillion atoms will create 364.821*1.35 sextillion, or 492.5088 sextillion MeV. Interestingly, this is equal to 492.5 nonillion electron volts, or 4.295 MegaYottaElectronvolts
492.5088 sextillion MegaElectonvolts is also equal to roughly 78,909 Megajoules, or 18.86 tons of TNT equivalent
This is rather big. but not massively so. The smallest nuclear bomb, the W54, had a yield of between 10 and 1000 tons of TNT. The largest conventional bomb, the GBU-43/B MOAB, has a yield of roughly 11 tons. The M67 grenade uses 180 grams of TNT-RDX mixture. So while the Helium-2 baloon bomb would be larger than all conventional bombs, it would still be smaller than most nukes.
- That looks great! Sorry I can't talk to you on your talk page, it hasn't been created and I've always been too lazy to make an autoconfimed user. I hope you're okay with the changes in this edit. Do you mind if we subst: this into the collapse box on 2649 so it can be cleaned up formatted there? Thanks for looking all that up. 172.70.207.8 14:37, 24 July 2022 (UTC)
