Difference between revisions of "Talk:2991: Beamsplitters"
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A difference of 5 magnitudes corresponds to a factor of 100 in brightness. The sun has magnitude -27, and Vega (by definition) is magnitude 0. This means that at Earth, the sun is 6e10 times brighter than Vega. Therefore a 10m diameter telescope (78.5 m^2) collects as much energy from Vega as a solar panel of size 1.23e-9 m^2, or a square 35 microns on a side. The brightest star, Sirius, is magnitude -1.46, which makes our 10m telescope equivalent to a square solar panel 70 microns on a side. (This calculation is a bit rough. To do it properly, we'd need to know the wavelength band which the solar panel can transform into electricity, and the magnitudes of the sun and star at that specific wavelength band.) [[Special:Contributions/198.41.236.144|198.41.236.144]] 03:08, 2 October 2024 (UTC) | A difference of 5 magnitudes corresponds to a factor of 100 in brightness. The sun has magnitude -27, and Vega (by definition) is magnitude 0. This means that at Earth, the sun is 6e10 times brighter than Vega. Therefore a 10m diameter telescope (78.5 m^2) collects as much energy from Vega as a solar panel of size 1.23e-9 m^2, or a square 35 microns on a side. The brightest star, Sirius, is magnitude -1.46, which makes our 10m telescope equivalent to a square solar panel 70 microns on a side. (This calculation is a bit rough. To do it properly, we'd need to know the wavelength band which the solar panel can transform into electricity, and the magnitudes of the sun and star at that specific wavelength band.) [[Special:Contributions/198.41.236.144|198.41.236.144]] 03:08, 2 October 2024 (UTC) | ||
| + | :Suppose that telescope was aimed towards Vega on a sunny day with a clear sky, with a path that didn't intersect the sun. How much brighter is the sky itself, from scattered sunlight, than Vega? There are a lot of factors that would make a great deal of difference, but suppose we assume that the sun is directly overhead. [[User:BunsenH|BunsenH]] ([[User talk:BunsenH|talk]]) 19:42, 2 October 2024 (UTC) | ||
Revision as of 19:42, 2 October 2024
Pictures taken by telescope are filtered one colour at the time. If the filtered out colours could be diverted, those photons could be harvested without interfering with the scientific studies. Of course, it would still not be economically efficient. 162.158.127.100 00:33, 28 September 2024 (UTC)
- Yes, a classic beam-splitter was the first color TV cameras. Three camera tubes (probably vidicons?) on the three outputs of two filtering beamsplitters. Later they did it all in one bottle; still later three chips on two beamsplitters. Color TV can be whacky. --PRR (talk) 01:35, 28 September 2024 (UTC)
The wavefunction explanation at the time the electron is generated is "wrong". The photovoltaic cell and the electron get entangled. See Wigner's Friend watching Schrödinger's Cat. Sebastian --172.68.110.188 16:19, 30 September 2024 (UTC)
- Please edit accordingly, with my thanks! 172.68.22.8 16:31, 30 September 2024 (UTC)
A difference of 5 magnitudes corresponds to a factor of 100 in brightness. The sun has magnitude -27, and Vega (by definition) is magnitude 0. This means that at Earth, the sun is 6e10 times brighter than Vega. Therefore a 10m diameter telescope (78.5 m^2) collects as much energy from Vega as a solar panel of size 1.23e-9 m^2, or a square 35 microns on a side. The brightest star, Sirius, is magnitude -1.46, which makes our 10m telescope equivalent to a square solar panel 70 microns on a side. (This calculation is a bit rough. To do it properly, we'd need to know the wavelength band which the solar panel can transform into electricity, and the magnitudes of the sun and star at that specific wavelength band.) 198.41.236.144 03:08, 2 October 2024 (UTC)
- Suppose that telescope was aimed towards Vega on a sunny day with a clear sky, with a path that didn't intersect the sun. How much brighter is the sky itself, from scattered sunlight, than Vega? There are a lot of factors that would make a great deal of difference, but suppose we assume that the sun is directly overhead. BunsenH (talk) 19:42, 2 October 2024 (UTC)
