Editing 2689: Fermat's First Theorem
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==Explanation== | ==Explanation== | ||
+ | {{incomplete|Created by a BACON ANT - Please change this comment when editing this page. Do NOT delete this tag too soon.}} | ||
+ | This is a reference to {{w|Fermat's Last Theorem}}, humorously implying that Fermat created a similar theorem as a child. Fermat's Last Theorem states that no three positive integers a, b, and c satisfy the equation a<sup>n</sup>+b<sup>n</sup>=c<sup>n</sup> for any integer value of n greater than 2. It is notable for having remained unproved for hundreds of years, despite many attempts to prove it, before {{w|Andrew Wiles}} finally succeeded in the 1990s. | ||
− | + | Little Fermat didn't try to prove the mathematical equation, but simply tried to read it as words, treating the "+" sign as a "t" so that "A<sup>N</sup>+" can be read as "ANT". His interpretation was quickly disproved because there's no "A" between "B" and "C", and no "O" bectween "C" and "N". | |
− | + | In the title text, the "words" are "ANT BNECN", treating the "=" as an "E"; "=" doesn't really look like "E", but it does have in common with E (and no other letter) both having several horizontal bars and being symmetric around a horizontal axis, and it's pronounced "equals" which begins with "E". The text then references Wiles, asserting that he proved this modified form of Fermat's First Theorem as well by cooking this "ant bnecn" (whatever "bnecn" is) as breakfast. | |
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− | In the title text, the "words" are "ANT BNECN", treating the | ||
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==Transcript== | ==Transcript== | ||
+ | {{incomplete transcript|Do NOT delete this tag too soon.}} | ||
− | :[A Hairy-like boy, representing Pierre de Fermat as a child, stands at a blackboard holding a piece of chalk. To his right is Miss Lenhart. The following text is | + | :[A Hairy-like boy, representing Pierre de Fermat as a child, stands at a blackboard holding a piece of chalk. To his right is Miss Lenhart. The following text is written on the blackboard:] |
:A<sup>N</sup> + B<sup>N</sup> = C<sup>N</sup> | :A<sup>N</sup> + B<sup>N</sup> = C<sup>N</sup> | ||
:SPELLS | :SPELLS |